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.29x^2-70.01x+4200.6=0
a = .29; b = -70.01; c = +4200.6;
Δ = b2-4ac
Δ = -70.012-4·.29·4200.6
Δ = 28.704100000001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70.01)-\sqrt{28.704100000001}}{2*.29}=\frac{70.01-\sqrt{28.704100000001}}{0.58} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70.01)+\sqrt{28.704100000001}}{2*.29}=\frac{70.01+\sqrt{28.704100000001}}{0.58} $
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